WebMarch 15, 2024 - 48 likes, 1 comments - Qookie Games (@qookie_games) on Instagram: "#Repost @zahidgames • • • • • • United Kingdom Previously I was using ... WebJul 30, 2024 · 5. As from @RobAu 's comment the title is misleading because you returns the index of the first unique character in your frequencies array so that the index 0 refers to the 'a' char, 1 refers to the 'b' char, etc., making the assumption that your string just contains only letter chars coerent with the ascii table.
387. 字符串中的第一个唯一字符 - 力扣(Leetcode)
WebSo the solution for this problem can be obtained by counting the occurrence of each character in a string and we are looking for unique characters so it must occur only … WebMar 4, 2024 · We iterate through the string s again using another for loop and return the index of the first character with a frequency of 1. For each character in the string s, we check if its frequency in the freq dictionary is 1. If it is 1, we return the index of that character in the string. If we do not find any character with a frequency of 1, we ... son of punch
First Unique Character in a String JavaScript - Medium
WebFirst Unique Character in a String - Given a string s, find the first non-repeating character in it and return its index. If it does not exist, return -1. Example 1: Input: s = "leetcode" Output: 0 Example 2: Input: s = "loveleetcode" Output: 2 Example 3: Input: s = "aabb" … Can you solve this real interview question? First Unique Character in a String - … WebFirst Unique Character in a String LeetCode Solution – Given a string s , find the first non-repeating character in it and return its index. If it does not exist, return -1. Example … WebFirst Unique Character in a String – Solution in Python class Solution(object): def firstUniqChar(self, s): freq = Counter(s) for e in s : if freq[e] == 1 : return s.index(e) return … son of ragnar