Focal chord of y 2 16x is a tangent

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August undefined, 2024

WebThe equation of a common tangent to the curves, y 2=16x and xy=−4 is A x+y+4=0 B x−2y+16=0 C 2x−y+2=0 D x−y+4=0 Medium Solution Verified by Toppr Correct option is D) Step 1: Use slope form of tangent equation of parabola Equation of tangent to parabola y 2=4ax in terms of slope ’m’ is y=mx+ ma WebFocal chord to y 2 = 16 x i s t a n g e n t t o (x − 6) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are Q. The focal chord to y 2 = 16 x is tangent to ( x − 6 ) 2 …

Answered: If a focal chord of y =16x is a tangent… bartleby

WebSolution : tangent to the parabola y 2 = 9x is. y = mx + 9 4 m. Since it passes through (4,10) ∴ 10 = 4m + 9 4 m 16 m 2 – 40m + 9 = 0. m = 1 4, 9 4. ∴ Equation of tangent’s are y = x 4 + 9 & y = 9 x 4 + 1. Hope you learnt equation of tangent to parabola in point form, slope form and parametric form, learn more concepts of parabola and ... WebFocal chord to y2=16x is tangent to x−62+y2=2 then the. Focal chord to y2 =16x is tangent to (x−6)2+y2 =2 then the possible values of the slopes of this chord (s),are. … in415c

If the fotal chord y = mx + c of parabola y^2=-64x is also the tangent …

WebAny chord through focus is called a focal chord and any chord perpendicular to ... 9 3 x 2 y2 Ex.2 Find the equation of the straight lines joining the foci of the ellipse 1 to the 25 16 x 2 y2 foci of the ... parallel to the line y + 2x = 4. Ex.2 Equation of the tangent to an ellipse 9x2 + 16y2 = 144 passing from (2, 3). ... WebThe focal chord of the parabola (y−2) 2=16(x−1) is a tangent to the circle x 2+y 2−14x−4y+51=0, then the focal chord can be A 0 B 1 C 2 D 3 Medium Solution Verified by Toppr Correct option is B) Was this answer helpful? 0 0 Similar questions If points (au 2,2au) and (av 2,2av) are extremities of the focal chord of a parabola y 2=4ax, then Hard WebThe focal chord to \( y^{2}=16 x \) is tangent to \( (x-6)^{2}+y^{2}=2 \), then the possible values of theslope of this chord are\( P \)(a) \( \{-1,1\} \)\( ... imx8 can bus

If a focal chord to y 2=16 x is tangent to x 62+ y 2=2, then the ...

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WebJan 23, 2024 · Solution For The focal chord to y2=16x is tangent to (x−6)2+y2=2, then the possible values of the slope of this chord, are The world’s only live instant tutoring platform. About Us Become a Tutor. Filo instant Ask button for chrome browser. Now connect to a tutor anywhere from the web ... WebMar 14, 2024 · Consider a parabola y 2 = 4 a x , parameterize it as x = a t 2 and y = 2 a t, then it is found that if we have a line segment passing through focus, with each points having value of t as t 1 and t 2 for the parameterization, then it must be that: t 1 ⋅ t 2 = − 1 Hope for hints. conic-sections Share Cite Follow edited Mar 14, 2024 at 15:05 imx8 familyWebFocal chord to y 2=16 x is tangent to x 62+ y 2=2 then the possible values of the slopes of this chords,areA. 1,1B. 2,2C. 2, 1/2D. 2, 1/2 Question Focal chord to y 2 = 16 x i s t a n g e n t t o ( x − 6 ) 2 + y 2 = 2 then the possible values of the slopes of this chord(s),are imx8 opencl移植

"WebHere, the focal chord of y 2 = 16 x is tangent to circle (x − 6) 2 + y 2 = 2 ⇒ Focus of parabola as (a, 0) i.e. (4, 0) Now, tangents are drawn from (4, 0) to (x − 6) 2 + y 2 = 2. Since, P A is tangent to circle. ∴ t a n θ = slope of tangent = A C A P = √ 2 √ 2 = 1, or B C B P = − 1. ∴ Slope of focal chord as tangent to circle ... " - Focal chord of y 2 16x is a tangent

Focal chord of y 2 16x is a tangent

Equation of Tangent to Parabola in all Forms - Mathemerize

Web2) are the endpoints of a focal chord then t 1 t 2 = −1. (2) Tangents at endpoints of a focal chord are perpendicular and hence intersect on directrix. (3) Length of a focal chord of y2 = 4ax, making an angle αwith the X-axis, is 4acosec2α. (4) If AB is a focal chord of y2 = 4ax, then , where S is the focus. Recall WebThe focal chord to y2 = 16x is tangent to (x – 6)2 + y2 = 2, then the possible values of the slope of this chord, are (2003S)a){–1, 1}b){–2, 2}c){–2, –1/2}d){2, –1/2}Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE ...

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WebJan 11, 2024 · The focal chord to `y^2=16x` is tangent to `(x-6)^2+ y^2 =2` then the possible values of the slope of this chord asked Nov 15, 2024 in Parabola by kundansingh ( 95.2k points) class-12 WebHere, the focal chord of y 2=16x is tangent to circle (x−6) 2+y 2=2⇒ focus of parabola as (a,0) i.e (4,0)⇒ centre and radius of circle is (6,0) and 2 respectivelyThus the equation of …

WebA: Here, Circle with center O is having tangents JK, KL and JL. so JA¯≅JB¯ ⇒JA=JB (tangent to circle… question_answer Q: Find the surface area of the cone in terms of it. WebMay 6, 2016 · Question: Prove that the directrix is tangent to the circles that are drawn on a focal chord of a parabola as diameter. ... Prove that in a parabola the tangent at one end of a focal chord is parallel to the normal at the other end. 0.

WebMath Advanced Math If a focal chord of y =16x is a tangent to the circle (x-6)° +y² = 2, then the positive value of the slope of this chord is. If a focal chord of y =16x is a … WebGet an expert solution to The focal chord of the parabola ( y − 2 ) 2 = 16 ( x − 1 ) is a tangent to the circle x 2 + y 2 − 14 x − 4 y + 51 = 0 , then slope of the focal chord can be

WebOct 14, 2024 · The focal chord to y^2 =16x is tangent to (x–6)^2 +y2 = 2, then the possible value of the slope of this chord, are asked Oct 22, 2024 in Parabola by deepikaben ( …

WebMar 14, 2024 · It is given that the focal chord is tangent to the circle which means that the distance of the focal chord from the center of the circle is equal to the radius of the circle. Therefore, we get m x − y − 4 m 1 + m 2 = 2 Now we will put the value of x = 6 and y = 0 in the above equation, we get ⇒ 6 m − 0 − 4 m 1 + m 2 = 2 imx8 chipsetWebT is a point on the tangent to a parabola y 2 = 4ax at its point P. TL and TN are the perpendiculars on the focal radius SP and the directrix of the parabola respectively. Then. A. SL = 2 (TN) B. 3 (SL) = 2 (TN) C. ... Let PSQ be the focal chord of … imx8 openclWebIf the fotal chord y = mx + c of parabola y^2=-64x is also the tangent to the circle 〖(x+10)〗^2+y^2=4 then absolute value of 4√2(m+c) is (a) 31(b) 32(c... in4370aWebThe focal chord to y2 =64x is tangent to (x−4)2+(y−2)2 =4 then the possible values of the slope of this chord is Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then the possible value of the slope of this chord are Q. The focal chord to y2 =16x is tangent to (x−6)2+y2 =2, then slope of focal chord is Q. in44tWebQ.3 Find the equations of the tangents to the parabola y2 = 16x, which are parallel ... y = 2x + 1 (C) 2y = x + 8 (D) y = x + 2 Q.10(a) The slope of the focal chords of the parabola y2 = 16x which are tangents to the circle (x ... [ JEE 2003 (Scr.)] Q.6 The line 2x + 6 y = 2 is a tangent to the curve x2 – 2y2 = 4. The point ... in4180 cyberopsWebApr 10, 2024 · Even by your method where it seems you are first finding equation of tangent to the circle and equating it to the focal chord, Given the equation of the circle, taking … in421r anexo ivWebClick here👆to get an answer to your question ️ The focal chord to y ^ 2 = 16 x is tangent to ( x - 6 ) ^ 2 + y ^ 2 = 2 then the possible values of the slope of this chord are Solve Study Textbooks Guides in4610bbfa